A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 33.0 m/s. what distance did it travel during this time?

880m

220m

440m

50m

Question

Physics

Kason

16 August, 08:29

A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 33.0 m/s. what distance did it travel during this time?

880m

220m

440m

50m

+5

Answers (1)

Know the Answer?

Nasir Hardin · Answer 1

Since the acceleration is uniform, we can calculate it from the data we are given:

a = (vf - vi) / 2

where vf=33 m/s and vi=11 m/s

Then use Suvat's equation:

x (t) = vi*t + 0.5 * a * t

where t=20s

A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 33.0 m/s. what distance did it travel during this time?880m220m440m50m

A car travels at uniform acceleration over a tine interval of 20.0s. its initial velocity is 11.0m/s and its final velocity is 33.0 m/s. what distance did it travel during this time?

880m

220m

440m

50m