A ball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. Its position function is s (t) = - 16t2 + 10t + 100. What is its velocity in ft/sec when t = 2 seconds?

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Physics

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12 September, 22:06

A ball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. Its position function is s (t) = - 16t2 + 10t + 100. What is its velocity in ft/sec when t = 2 seconds?

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Answers (1)

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Ben Colon · Answer 1

All you need to know is that velocity is the derivative with respect to time of position.

Therefore: ds/dt = - 32t + 10

To know the velocity at t=2s you just need to plug t=2 for t in the equation above.