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16 November, 14:28

A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2. It attains a velocity 52m/s. calculate the distance covered during the journey.

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  1. 16 November, 18:04
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    distance=46m

    Explanation:

    initial velocity (u) = 40m/s

    final velocity (v) = 52m/s

    acceleration=12m/s²

    distance (s) = ?

    v²=u²+2as (using equ. of motion)

    (52) ² = (40) ²+2 (12) s

    2704=1600+24s

    24s=2704-1600

    24s=1104

    s=1104/24

    s=46m
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