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6 June, 17:28

Your tennis ball rolls off a 0.91m tall table and hits 0.25m out from the table. What is it's time in the air? What is its vertical velocity before hitting the ground (show work)

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  1. 6 June, 19:50
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    consider the motion of the ball in vertical direction after it rolls off the table

    v₀ = initial velocity of the ball in vertical direction = 0 m/s

    a = acceleration = acceleration due to gravity = 9.8 m/s²

    Y = vertical displacement = height of the table = 0.91 m

    t = time spent in air by the ball

    Using the kinematics equation

    Y = v₀ t + (0.5) a t²

    0.91 = 0 t + (0.5) (9.8) t²

    t = 0.43 sec

    v = final velocity in vertical direction just before it hits the ground

    Using the kinematics equation

    v = v₀ + at

    v = 0 + (9.8) (0.43)

    v = 4.21 m/s
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