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24 December, 16:41

After being struck by a bowling ball, a 1.7 kg bowling pin sliding to the right at 3.8 m/s collides head-on with another 1.7 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s.

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  1. 24 December, 20:15
    0
    3 m/s

    Explanation:

    Parameters given:

    Mass of first bowling pin, m = 1.7 kg

    Initial velocity of first bowling pin, u = 3.8 m/s

    Final velocity of first bowling pin, v = 0.8 m/s

    Mass of second bowling pin, M = 1.7 kg

    Initial velocity of second bowling pin, U = 0 m/s

    Let the final velocity of the second bowling pin be V

    Using the principle of conservation of momentum:

    Total initial momentum = Total final momentum

    m*u + M*U = m*v + M*V

    (1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)

    6.46 = 1.36 + 1.7V

    1.7V = 5.1

    V = 5.1/1.7 = 3 m/s
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