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22 October, 16:34

The equation of trajectory of a projectile is y=10x - (5/9) x^2 if we assume g=10m/s^2, the range of projectile in meters is?

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  1. 22 October, 17:23
    0
    18 m

    Explanation:

    y = 10x - 5/9 x²

    When the projectile lands, y=0:

    0 = 10x - 5/9 x²

    0 = x (10 - 5/9 x)

    x = 0, 18

    The range of the projectile is 18 m.
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