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16 January, 10:23

When you stretch a spring 20 cm past its natural length, it exerts a force of 8

N. What is the spring constant of this spring?

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Answers (1)
  1. 16 January, 10:48
    0
    40 N/m

    Explanation:

    F = - kx (This is the Hooke's Law equation)

    F is the force the spring exerts = 8 N

    -k = spring constant

    x = displacement (The distance stretched past it's natural length) = 20cm

    x needs to be in meters, and 20 cm is = to 0.2 meters

    Finally:

    8N = - k (0.2m)

    -k = 8N / 0.2 m

    k = - 40 N/m
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