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25 January, 08:02

Albert dressed as TWO-FACE flips a coin up in the air at an upward velocity of 5.00 m/s. He fails to catch it on the way down and it falls down an 8.5 m deep well. Calculate the maximum height and maximum magnitude (could be positive or negative) of velocity of the coin.

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  1. 25 January, 10:30
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    1.28 m, 14 m/s

    Explanation:

    At the maximum height, the velocity is 0.

    Given:

    a = - 9.8 m/s²

    v₀ = 5.00 m/s

    v = 0 m/s

    x₀ = 0 m

    Find:

    x

    v² = v₀² + 2a (x - x₀)

    (0 m/s) ² = (5.00 m/s) ² + 2 (-9.8 m/s²) (x - 0 m)

    x = 1.28 m

    The maximum speed is at the bottom of the well.

    Given:

    a = - 9.8 m/s²

    v₀ = 5.00 m/s

    x₀ = 0 m

    x = - 8.5 m

    Find:

    v

    v² = v₀² + 2a (x - x₀)

    v² = (5.00 m/s) ² + 2 (-9.8 m/s²) (-8.5 m - 0 m)

    v = - 13.8 m/s

    Rounded to 2 sig-figs, the maximum speed is 14 m/s.
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