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26 November, 03:41

If a projectile is fired with an initial velocity of V meters per second at an angle A above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations

x = (Vcos (A)) t,

y = (Vsin (A)) t-12gt2,

A gun is fired with a = 30° and v0 = 500 m/s. When will the bullet hit the ground?

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  1. 26 November, 06:18
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    The projectile will hit the ground after about 1min 41 seconds

    T=100.7 seconds

    Explanation:

    The time of flight for a projectile motion is expressed as

    T = (2usin0) / g

    Where u is the initial velocity

    Theta 0 is the projected angle

    Assuming g=9.81m/s

    Given data

    Theta 0 = 30°

    u = 500m/s

    Substituting our data into the expression we have

    T = (2*500*sin30°) / 9.81

    T = (1000*-0.988) / 9.81

    T=988/9.81

    T=100.7 second

    The projectile will hit the ground after about 1min 41 seconds
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