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15 December, 05:57

If a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?

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  1. 15 December, 07:29
    0
    0.1 N

    Explanation:

    Considering that Hooke's law, F=xk where k is the spring constant in N/m, x is extension in meters, F is spring force in N.

    Converting the given extension from cm to m, we divide by 100 hence 5/100=0.05 m

    Substituting 0.05 m for x and 2 N/m for k then the spring force will be

    F=2*0.05=0.1 N
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