A weight lifter lifts a 200N barbel above his head from the floor to the height of 2M. He holds the barbel for 5 seconds how much work does he do during the 5s interval of time

Question

Physics

Carla Richard

2 November, 01:04

A weight lifter lifts a 200N barbel above his head from the floor to the height of 2M. He holds the barbel for 5 seconds how much work does he do during the 5s interval of time

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Answers (1)

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Rolando Huffman · Answer 1

400 J

Explanation:

Work: This can be defined as the product of force and distance along the direction of the force. The standard unit of work is Joules (J).

From the question,

The work done by the weight lifter = Weight of the barbel*height

E = W*h ... Equation 1

Where E = work done by the weight lifter, W = weight of the barber, h = height.

Given: W = 200 N, h = 2 m

Substitute these values into equation 1

E = 200*2

E = 400 J.

Hence he does 400 J of work during the 5s interval