Convert the acceleration of a free falling body 9.8 m/s^2 to ft/s^2

Question

Physics

Clay Henry

18 September, 00:02

Convert the acceleration of a free falling body 9.8 m/s^2 to ft/s^2

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Answers (2)

Know the Answer?

Veronica Goodman · Answer 1

i hoping this is the right answer : Use A = log (100/%T) = 2.0 - log %T

a) A = 2.00 - log 53.86 = 2.00 - 1.73 = 0.27

b) A = 2.00 - log 0.56 = 2.00 + 0.25 = 2.25

i feel like ur going to delete this but i tried

Kasey Salas · Answer 2

hoping this is the right answer : Use A = log (100/%T) = 2.0 - log %T

a) A = 2.00 - log 53.86 = 2.00 - 1.73 = 0.27

b) A = 2.00 - log 0.56 = 2.00 + 0.25 = 2.25

i feel like ur going to delete this but i tried