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19 February, 05:32

Jim quadruples the distance between himself and a sound source. What is the change in decibels of the sound he hears?

A. - 6 dB

B. - 12 dB

C. + 6 dB

D. + 12 dB

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Answers (1)
  1. 19 February, 07:34
    0
    Quadrupling the distance reduces the sound to 1/16 of its original intensity.

    10 log (1/16) = - 12 dB (choice-B)
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