What will the angle of refraction be for a ray of light passing from air into a sodium chloride crystal if the angle of incidence is 60.0°? The index of refraction of sodium chloride is 1.53.

A. 13°

B. 22°

C. 34°

D. 42°

E. 48°

Using Snell's Law:

n1 * sin (theta1) = n2 * sin (theta2)

where

n1 is the refractive index of the incident light (n1 = 1 in this case)

theta1 is the angle of incidence

n2 is the refractive index of the material that the light is entering (n2 = 1.53 in this case)

theta2 is the angle of refraction

n1 * sin (theta1) = n2 * sin (theta2)

becomes

1 * sin (60) = 1.53 * sin (theta2)

or

1 * 0.866 = 1.53 * sin (theta2)

0.866 = 1.53 * sin (theta2)

sin (theta2) = 0.866 / 1.53 = 0.566

theta2 = arcsin (0.566) = 34 degrees (the angle of refraction)

It should be 34 degrees because i took the test

Explanation:

Took the test