Ask Question
31 July, 22:33

A coil of conducting wire carries a current i. In a time interval of Δt = 0.530 s, the current goes from i1 = 3.60 A to i2 = 2.20 A. The average emf induced in the coil is e m f = 16.0 mV. Assuming the current does not change direction, calculate the coil's inductance (in mH).

+3
Answers (1)
  1. 1 August, 02:00
    0
    Answer:6.1mH

    Explanation: The current - voltage relationship of an inductor is given below as

    v = L * Δi/Δt

    Where induced emf (v) = 16mv = 0.016v

    Inductance of inductor (L) = ?

    Δi = I1 - I2 = 3.6 - 2.2 = 1.4

    Δt = 0.53

    Δi/Δt = 1.4/0.53 = 2.642.

    By substituting the parameters, we have that

    0.016 = L * 2.462

    L = 0.016 / 2.462

    L = 0.0061 H = 6.1mH
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A coil of conducting wire carries a current i. In a time interval of Δt = 0.530 s, the current goes from i1 = 3.60 A to i2 = 2.20 A. The ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers