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18 October, 16:56

A skateboarder rolls horizontally off the top of a

staircase at a speed of 18 ms-1

and at the bottom of

the stairs which has a horizontal length of 9 m as

shown.

Calculate the skater's vertical displacement during

the jump?

+1
Answers (1)
  1. 18 October, 17:25
    0
    Given Information:

    Initial horizontal speed = Vx = 18 m/s

    horizontal distance = R = 9 m

    Required Information:

    Vertical displacement = h = ?

    Answer:

    Vertical displacement = h = 1.23 m

    Explanation:

    The horizontal distance covered by the skater is given by

    R = Vx*t

    Where R is horizontal distance, Vx is the initial horizontal speed and t is the time taken for the jump.

    t = R/Vx

    t = 9/18

    t = 0.5 seconds

    The vertical displacement covered by the skater is given by

    h = Vy*t + ½gt²

    Where Vy is the initial vertical speed of the skater and is zero since the skater jumps horizontally, g is the gravitational acceleration and h is the vertical displacement.

    h = 0*t + ½gt²

    h = ½gt²

    h = ½ (9.81) (0.5) ²

    h = 1.23 m

    Therefore, the vertical displacement of the skater is 1.23 m
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