Bottles of perfume sometimes have thick glass (n = 1.5 walls which give the impression the volume is larger than it is. assume a cylindrical bottle has an inner radius of 1 cm and an outer radius of 2 cm. how thick (in cm would the wall appear if you could see a mark on the inside surface?

Question

Physics

Miranda Dillon

19 January, 02:45

Bottles of perfume sometimes have thick glass (n = 1.5 walls which give the impression the volume is larger than it is. assume a cylindrical bottle has an inner radius of 1 cm and an outer radius of 2 cm. how thick (in cm would the wall appear if you could see a mark on the inside surface?

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Romeo Burke · Answer 1

The real thickness of the bottle is calculated by subtracting its inner radius from the outer radius. This gives us the answer of,

real thickness = (2 cm - 1 cm) = 1 cm

Then, the real thickness is multiplied by the value of n to get the thickness that it would appear to be.

1 cm x 1.5 = 1.5 cm