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12 August, 23:33

A conducting wire has a length of 3m and a resistance of 0.35 Ώ, when a potential difference is applied to the ends of the wire, a current of the 1.8 A is produced in it. What is the magnitude of the electric field inside the wire?

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  1. 12 August, 23:49
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    Answer: E = IR/L

    SO

    E = 1.8A*0.35Ω/3m=0.21
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