Ask Question
3 May, 09:31

a car travelled 60 km west in 1.33 h along straigt line, then returned back east for 40 km in 0.67 h. its average velocity

+3
Answers (1)
  1. 3 May, 12:05
    0
    7.29 km/h East

    Explanation:

    Velocity is distance covered per unit time, with consideration to the direction.

    Taking East as positive then West is negative

    Velocity when traveling towards West

    V=d/t where d is distance and t is time taken. Substituting 60 km dor d and 1.33 for t then

    V=-60/1.33=-45.112781954887 km/h West

    Velocity when traveling towards East

    V=d/t where d is distance and t is time taken. Substituting 40 km dor d and 0.67 for t then

    V=40/0.67=59.701492537313 km/h East

    Average velocity = (velocity East+West) / 2

    Average velocity is (59.701492537313+-45.112781954887) / 2=7.29 km/h

    Since the average is positive, then the direction is East

    Therefore, the average velocity is 7.29 km/h East
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “a car travelled 60 km west in 1.33 h along straigt line, then returned back east for 40 km in 0.67 h. its average velocity ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers