An object that starts at a position of 5 m and travels for 3 s at a velocity of - 9 m/s ends up at what position?

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Physics

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11 June, 19:14

An object that starts at a position of 5 m and travels for 3 s at a velocity of - 9 m/s ends up at what position?

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Answers (1)

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Alessandra Cunningham · Answer 1

So Velocity = final position - initial position divided by time. We are looking for The final position so let's plug in what we know and go from there.

V = - 9 m/s Xf = ? Xi = 5m T = 3s

to solve

-9 m/s = (X - 5m) / 3s

-9 x 3 = X - 5

-27 + 5 = X

Xf = 32 m (distance can't be in negative, so we disregard that)

(Hopefully this is right, I haven't done any physics since last year. But it shouldn't be too far off)