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23 October, 16:31

A new battery has an emf of 1,52 V. When a wire of negligible resistance is connected between the terminals of the battery, a current of 7,05 A is produced. Find the internal resistance of the battery.

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  1. 23 October, 20:13
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    r = V/i = 1.52/7.05 = 0.216 ohm
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