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21 May, 19:22

A wire 0.80m long carrying a current of 3.2A is perpendicular to a 0.15T magnetic field (B field). What

is the force on the wire? (Use F=BIL to solve!)

Input answer with 3 decimal places (for example: 555) and do NOT include the units!

E

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Answers (1)
  1. 21 May, 23:06
    0
    1.344 N

    Explanation:

    The expression for the for on a wire carrying current in a magnetic field is given as,

    F = BILsinФ ... Equation 1

    Where F = Force on the wire, B = magnetic field, I = current, L = Length of the wire, Ф = angle between the conductor and the magnetic field.

    Given: B = 0.15 T, I = 3.2 A, L = 0.8 m, Ф = 90° (perpendicular)

    Substitute into equation 1

    F = 0.15 (3.2) (0.8) (sin90°)

    F = 1.344 N

    Hence the Force on the wire = 1.344 N
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