Ask Question
19 November, 11:25

A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student then increases the weight on the newtonmeter by 2N. If the spring constant is 400N/m what is the total extension of the spring?

+1
Answers (1)
  1. 19 November, 13:59
    0
    5x10^-3

    Explanation:

    Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

    Hooke's Law can be represented as

    F = kx,

    where F is the force

    k is the spring constant

    x is the extension of the material

    Plug values in the equation

    Step 1 find the original extension

    0.045 = (400) x

    x = 1.125x 10^-4 m d

    Step 2 find the new extension

    0.045+2 = 400 (x)

    2.045 = 400x

    x = 5.1125x10^-3

    Step 3 subtract the new extension with original

    Total extension of the spring = 5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student then ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers