An elevator is initially moving upward at a speed of 12.60 m/s. The elevator experiences a constant downward acceleration of magnitude 3.60 m/s2 for 2.97 s.

Question

Physics

Jovanni Good

4 January, 12:19

An elevator is initially moving upward at a speed of 12.60 m/s. The elevator experiences a constant downward acceleration of magnitude 3.60 m/s2 for 2.97 s.

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Mariana Lynn · Answer 1

I'm assuming you're asking for the elevator's final velocity.

Consider the following equation:

Vf = Vi + aΔt

Vf is the final velocity.

Vi is the initial velocity.

a is the acceleration.

Δt is the amount of elapsed time.

Given values:

Vi = 12.60m/s

a = - 3.60m/s²

Δt = 2.97s

Substitute the terms in the equation with the given values and solve for Vf:

Vf = 12.60 - 3.60*2.97

Vf = 1.91m/s