As a tennis ball is struck, it departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horizontal distance of 19.6 m from the racket. How far above the court is the tennis ball when it leaves the racket?

Question

Physics

Gavin Reid

20 January, 11:53

As a tennis ball is struck, it departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horizontal distance of 19.6 m from the racket. How far above the court is the tennis ball when it leaves the racket?

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Answers (1)

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Arielle Strickland · Answer 1

solution:

long to travel 19.6m at 28m/s

t = 19.6/28

=time taken to drop from rest

s=ut + (1/2) at^2

u=0

a=~10

so s = (1/2) * 10 * (19.6/28) ^2 = 2.45m