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19 July, 07:57

A golfer rides in a golf cart at an average speed of 3.10 m/s for 23.0 s. She then gets out of the cart and starts walking at an average speed of 1.20 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.60 m/s

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  1. 19 July, 09:46
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    Answer;

    = 10.4 sec

    Explanation and solution;

    Average velocity = Total distance traveled/Total time

    Total distance traveled = 3.1 * 29 + 1.2 (T) = 89.9 + 1.2T

    where

    T = walking time of golfer

    Total time = 29 + T

    and substituting appropriately into Equation 1

    2.6 = (89.9 + 1.2T) / (29 + T)

    Simplifying the above,

    2.6 (29 + T) = 89.9 + 1.2T

    75.4 + 2.6T = 89.9 + 1.2T

    1.4T = 14.5

    T = 10.4 sec.
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