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2 September, 22:06

The concentration of carbon monoxide in an urban apartment is 48μg/m3. What mass of carbon monoxide in grams is present in a room measuring 10.6ft*14.8ft*20.5ft?

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  1. 3 September, 00:12
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    Answer;

    = 5.45 * 10-3 g or 5.45 mg

    Explanation;

    1 meter = 3.048 feet

    Volume = 10.6 * 14.8 * 20.5 ft³ * (1/3.048 ft/m³)

    = 113.57 m³

    Therefore; the mass of carbon monoxide;

    = 113.57 m³ * 48 * 10^-6 g/m³

    = 5.45 * 10^-3 g

    = 5.45 mg
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