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3 November, 12:31

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/. To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 6.3 s, what is the depth of the crater?

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  1. 3 November, 16:09
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    Answer;

    =32.15 meters

    Explanation;

    Use the formula

    s = ut + 0.5 a (t) ^2 to find out 's'

    where s = distance traveled

    u=initial velocity which is zero in this case

    t = time taken to travel 's' distance

    a=acceleration (due to gravity on moon i. e 1.62 m/s^2)

    Therefore;

    S = 0.5 * 1.62 * 6.3 * 6.3

    = 32.1489 meters

    Thus; the crater is 32.15 meters deep.
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