What must the charge (sign and magnitude) of a particle of mass 1.49 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 670 n/c?

Question

Physics

Taniya Rich

8 August, 00:00

What must the charge (sign and magnitude) of a particle of mass 1.49 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 670 n/c?

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Answers (1)

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Connor · Answer 1

Answer;

= - 2.18 * 10^-5 C

Explanation;

m = 1.49 * 10^-3 kg

Take downward direction as positive.

Fg = m g

E = 670 N/C

Fe = q E

Fe + Fg = 0

q E + m g = 0

q = - m g/E

= - 1.49 * 10^-3 * 9.81/670

= - 2.18 * 10^-5 C

= - 2.18 * 10^-5 C