A boat leaves a dock at 6:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due east at 15 km/h and reaches the same dock at 7:00 PM How many minutes after 6:00 PM were the two boats closest together

22 minutes

Explanation:

Let t be the time after 6 PM.

D be the distance

During time t, the First boat travelling south = 20t km.

Meanwhile, the second boat travelling east is = 15t km,

Then the second boat started 15 km from the dock, so the distance from the dock is = (15 - 15t) km.

The distance D between the two boats is is expressed as = (15 - 15t) ^2 + (20t) ^2 = D*2

Let differentiate with respect to time and making dD/dt to 0 (D minimization is important),

then 2 (15 - 15t) (-15) + 2 (20t) (20) = 0

Therefore t = 9/25 h or 0.36 h or 22 minutes