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16 October, 04:39

A Van de Graaff generator is charged so that the electric field at its surface is 88000 N/C. What is the magnitude of the electric force on a proton released at the surface of the generator? The mass of a proton is 1.6726 * 10-27 kg and the fundamental charge is 1.602 * 10-19 C. Answer in units of N.

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  1. 16 October, 06:56
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    Answer: 1.3617*10^-14 N

    Explanation: The formulae that relates electric field intensity, magnitude of charge and force is given by the formulae below.

    F = Eq

    Where F = electric force = ?

    E = strength of electric field = 88000 N/c

    q = magnitude of proton charge = 1.602*10^-19 c

    By substituting the parameters, we have that

    F = 88000 * 1.602*10^-19

    F = 13.617*10^-15

    F = 1.3617*10^-14 N
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