An athlete whirls an 8.2 kg hammer tied to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 1.85 rev/s. What is the centripetal acceleration of the hammer? Assume his arm length is included in the length given for the chain. Answer in units of m/s 2.

Question

Physics

Kaia Pearson

15 May, 02:33

An athlete whirls an 8.2 kg hammer tied to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 1.85 rev/s. What is the centripetal acceleration of the hammer? Assume his arm length is included in the length given for the chain. Answer in units of m/s 2.

+4

Answers (1)

Know the Answer?

Winston Meadows · Answer 1

mass of hammer, m = 8.2 kg

Length of chain, l = 1.4 m

angular frequency, f = 1.85 rev/s

Let the centripetal acceleration is a.

a = r x ω²

a = l x 4π² x f²

a = 1.4 x 4 x 3.14 x 3.14 x 1.85 x 1.85

a = 188.97 m/s²