Ask Question
28 August, 23:39

Q. A stone is projected at an angle of 30° with the

vertical. If the horizontal component of its velocity

is 9.8 m/s. Calculate the i) maximum height and

horizontal range

+1
Answers (1)
  1. 29 August, 02:19
    0
    1.63 m

    11.3 m

    Explanation:

    Given:

    v₀ₓ = 9.8 m/s

    v₀ᵧ = 9.8 tan 30° = 5.67 m/s

    aₓ = 0 m/s²

    aᵧ = - 9.8 m/s²

    Find: Δy given vᵧ = 0 m/s.

    vᵧ² = v₀ᵧ² + 2aᵧΔy

    (0 m/s) ² = (5.67 m/s) ² + 2 (-9.8 m/s²) Δy

    Δy = 1.63 m

    Find: Δx given Δy = 0 m.

    Δy = v₀ᵧ t + ½ aᵧt²

    0 m = (5.67 m/s) t + ½ (-9.8 m/s²) t²

    t = 1.15 s

    Δx = v₀ₓ t + ½ aₓt²

    Δx = (9.8 m/s) (1.15 s) + ½ (0 m/s²) (1.15 s) ²

    Δx = 11.3 m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Q. A stone is projected at an angle of 30° with the vertical. If the horizontal component of its velocity is 9.8 m/s. Calculate the i) ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers