In a circuit, a 100.-ohm resistor and a 200.-ohm resistor are connected in parallel to a 10.0-volt battery.

Determine the power dissipated by the 100.-ohm resistor.

Calculate the current in the 200.-ohm resistor.

The power dissipated is 1.49 watts.

Explanation:

To calculate the equivalent resistance of the two resistors Req

Req = 1: 1 / r1 + 1/r2

= 1 / 1/100 + 1/200

=66.67 ohm

To calculate the power dissipated by the 100 ohm resistor

1/RT = 1 / R1 + 1 / R2

= 1 / 100 + 1 / 200

=4 / 400 + 2 / 400

= 6 / 400

RT = 400 / 6

= 66.67 ohm

p₍max₎ = I * V P = I² * R

P = V² / RT

= 10² / 66.67

= 100 / 66.67

P = 1.49 watts

Thus the power dissipated is 1.49 watts.