A capacitor stores 7.6 * 10-11 C when the electric potential difference between the plates is 5.8 V. What is the electric potential energy stored in the capacitor?

Answ: 2.2 * 10-10 J

Energy stored in the capacitor = 2.2 x 10⁻¹⁰ J

Explanation:

The energy stored in the capacitor is given by

E = 1/2 q V

E = energy stored

q = charge = 7.6 x 10⁻¹¹ C

V = potential difference=5.8 V

so energy stored = E = 1/2 (7.6 x 10⁻¹¹) (5.8)

Energy stored = 2.2 x 10⁻¹⁰ J