A child is sitting on the outer edge of a merry-go-round that is 18 m in diameter. if the merry-go-round makes 5.9 rev/min, what is the velocity of the child in m/s?

Velocity of the child = 20008.1 m/s

Explanation;

diameter = 18 m

the linear velocity v is given by

v = r ω

r = radius=18/2 = 9 m

ω = 5.9 rev / min = 5.9 rev/min * [2π rad / 1 rev] * [60 s / 1 min]=2223.1 rad/s

so V = 9 (2223.1)

V = 20008.1 m/s

Answer: The velocity of the kid is 5.6 m/s

Explanation: Ok, the velocity of the kid will be:

v = w*r

where r is the radius, and w is the frequency.

We know that the diameter is 18m, and the diameter is equal to two times the radius. So r = 18m/2 = 9m

Now, we know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length, if the kid does 5.9 revolutions in one minute, then the kid spins at v = 5.9*2pi*9m/min

But we want to write this in meters per second, this means that we need to divide it by 60.

v = (5.9*2pi*9/60) m/s = 5.56 m/s