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1 July, 08:41

2. A force of 24x10² N exists between a positive charge of 8x10-5C and a positive charge of 3x10C.

What distance separates the charges?

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  1. 1 July, 11:28
    0
    Answer: 94.9 metres

    Explanation:

    Given that,

    Force between the two charges (F) = 24x10² N

    Negative charge (q1) = 8x10-5C

    Positive charge (q2) = 3x10C

    Distance between charges (r) = ?

    Apply the formula for

    F = (kq1q2) / r²

    Recall that k is Coulomb's constant with a value of 9 * 10^9 Nm2C-2

    Then,

    24x10² N = (9 * 10^9 Nm2C-2 x 8x10-5C x 3x10C) / r²

    24x10² N = (2.16 x 10^7) / r²

    r² = (2.16 x 10^7 / 24x10² N)

    r² = 9000

    To get the value of r, find the square root

    r = √9000

    r = 94.868m (rounded to the nearest tenth as 94.9m)

    Thus, a distance of 94.9 metres separates the charges.
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