wo charges - 72 microcoulomb and + 83 microcoulomb if the distance between them is 0.75m. Find the force of attraction.

Correct answer: Fc = 95.6 N

Explanation:

Fc = k q₁ q₂ / r² Coulomb force

where it was given:

k = 9 · 10⁹ N m²/C² dielectric constant,

q₁ = - 72 μC = - 72 · 10⁻⁶ C

q₂ = + 83 μC = + 83 · 10⁻⁶ C

r = 0.75 m = 75 · 10⁻² m distance between charges

Since the given charges are opposite between them exist force of attraction.

Fc = k q₁ q₂ / r² = 9· 10⁹ · 72 · 10⁻⁶ · 83 · 10⁻⁶ / (75 · 10⁻²) ²

Fc = 53,784 · 10⁻³ / 5,625 · 10⁻⁴ = 9.56 · 10⁻³ · 10⁴ = 9.56 · 10 = 95.6 N

Fc = 95.6 N

God is with you!