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13 April, 00:55

A bullet of mass 6g travelling at 120 meter's per second penetrates

deep into a fixed target and is brought to rest in 0.01

seconds. Find;

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Answers (1)
  1. 13 April, 01:00
    0
    Answer: U = 120 m/s

    v = 0

    t = 0.01 s

    a = (v-u) / t = - 120 / 0.01 = - 12000 m/s

    a) S = (v² - u²) / 2a = - 120² / 2 * (-12000) = 120 / 200 = 0.6 m

    distance of penetration is 0.6m

    b) force = ma = 0.005*12000 = 60N
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