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6 June, 14:29

Two stationary carts are tied together by a thread with a compressed spring held between them. When the thread is cut, the two carts move apart. After the spring is released, one cart m = 3.00 kg travels east with a velocity of 0.82 m/s. What is the magnitude of the velocity of the second cart (m = 1.70 kg) after the spring is released?

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  1. 6 June, 15:08
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    1.45 m/s

    Explanation:

    The spring exerts equal and opposite forces on the carts.

    Therefore, the impulses on the carts are equal and opposite.

    J₁ = - J₂

    m₁Δv₁ = - m₂Δv₂

    (3.00 kg) (0.82 m/s - 0 m/s) = - (1.70 kg) (v - 0 m/s)

    v = - 1.45 m/s

    The magnitude of the second cart's velocity is 1.45 m/s.
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