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3 March, 17:29

A metal rod has a moves with a constant velocity of 40 cm/s along two parallel metal rails through a magnetic field of 0.575 T. If the rails are separated by 20 cm, what is the power generated by the rod? O 341 x 1ow O 6.98 x 103 w O 9.00x 10sw O 8.10 x 105w

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  1. 3 March, 17:46
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    2.12/R mW

    Explanation:

    The electrical power, P generated by the rod is

    P = B²L²v²/R where B = magnetic field = 0.575 T, L = length of metal rod = separation of metal rails = 20 cm = 0.2 m, v = velocity of metal rod = 40 cm/s = 0.4 m/s and R = resistance of rod = ?

    So, the induced emf on the conductor is

    E = BLv

    = 0.575 T * 0.2 m * 0.4 m/s

    = 0.046 V

    = 46 mV

    The electrical power, P generated by the rod is

    P = B²L²v²/R

    = B²L²v²/R

    So, P = (0.575 T) ² * (0.2 m) ² * (0.4 m/s) ²

    = 0.002116/R W

    = 2.12/R mW
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