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26 August, 15:00

Calculate the impulse of a 0.140 kg baseball that starts at rest on a tee and reaches a final velocity of 20 m/s after being struck with a force of 100 N.

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  1. 26 August, 15:27
    0
    impulse = change in momentumF*t = m (v-u) I = 0.140 (20-0) I = 0.140 * 20I = 2.8NS
  2. 26 August, 16:17
    0
    Answer: 2.8 Ns

    Explanation:

    Given that,

    impulse I = ?

    Mass of baseball M = 0.140 kg

    Initial velocity (at rest) Vi = 0m/s

    final velocity Vf = 20 m/s

    force F = 100 N

    Recall that impulse is the product of force and the time during which it acts

    i. e Impulse = Force x Time

    (since impulse is also equal to change in momentum, then

    impulse = Ft = M x (Vf - Vi)

    So, apply I = M x (Vf - Vi)

    I = 0.140kg x (20 m/s - 0 m/s)

    I = 0.140kg x (20 m/s)

    I = 2.8 Ns

    Thus, the impulse of the baseball is 2.8 Ns
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