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23 June, 10:51

A 1.45 kg 1.45 kg falcon catches a 0.415 kg 0.415 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 26.5 m/s 26.5 m/s and the dove's velocity is 4.35 m/s 4.35 m/s in the same direction?

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  1. 23 June, 14:35
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    Answer: The velocity is 21.5m/s

    Explanation:

    Let's call:

    M1 and V1 as the mass and velocity of the falcon:

    M1 = 1.45kg

    V1 = 26.5m/s

    M2 and V2 as the mass and velocity of the dove:

    M2 = 0.415kg

    V2 = 4.35m/s

    Where both velocities are positive because both animals move in the same direction.

    We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:

    V = (V1*M1 + V2*M2) / (M1 + M2)

    V = (1.45kg*26.5m/s + 0.415kg*4.35m/s) / (1.45kg + 0.415kg) = 21.5m/s
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