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28 May, 02:11

A 163 ‑turn circular coil of radius 2.65 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. The coil is connected to a 10.7 Ω resistor to create a closed circuit. During a time interval of 0.149 s, the magnetic field strength decreases uniformly from 0.481 T to zero. Find the energy, in millijoules, that is dissipated in the resistor during this time interval.

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  1. 28 May, 03:19
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    change in flux = no of turns x area of coil x change in magnetic field

    = 163 x π 2.65² x 10⁻⁴ x (.481 - 0)

    = 1728.84 x10⁻⁴ weber

    rate of change of flux = change in flux / time

    = 1728.84 x10⁻⁴ /.149

    = 11603 x10⁻⁴ V.

    volt induced = 1.16 V

    current in the circuit

    = volt induced / resistance

    1.16 / 10.7 =.1084 A

    energy dissipated = i²Rt where i is current, R is resistance and t is time.

    =.1084² x 10.7 x. 149

    =.018734 J

    = 18.73 mJ.
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