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6 July, 06:07

Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, straight wire. If you were unfortunate enough to be 4.9 m away from such a lightning bolt, how large a magnetic field would you experience

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  1. 6 July, 06:13
    0
    Answer: 8.16*10^-4 T

    Explanation:

    Given

    Current of the lightening bolt, I = 20 kA

    Distance from the strike of the lightening bolt, r = 4.9 m

    To solve, we use the formula

    B = [μ (0) * I] / 2πr, where

    B = magnetic field of the lightening

    μ = permeability constant = 4π*10^-7 N/A²

    I = current of the lightening

    r = distance from the lightening strike

    B = [ (4 * 3.142*10^-7) * 20*10^3] / (2 * 3.142 * 4.9)

    B = (12.568*10^-7 * 20*10^3) / 6.284 * 4.9

    B = 0.025 / 30.79

    B = 8.16*10^-4 T

    The magnetic field to be experienced would be 8.16*10^-4 T large
  2. 6 July, 07:17
    0
    how large a magnetic field would you experience = 8.16 x 10∧-4T

    Explanation:

    I = 20KA = 20,000A

    r = 4.9 m

    how large a magnetic field would you experience = u. I/2πr

    how large a magnetic field would you experience = (4π x10∧-7) * 20000/2π * 4.9

    how large a magnetic field would you experience = 8.16 x 10∧-4T
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