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30 September, 05:06

What is the power usage of a device that uses 3.0 A of current at a voltage of 120 V? How much energy (in kilowatt-hours) does this device use if it is left on for 2.0 hr?

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Answers (2)
  1. 30 September, 06:13
    0
    360 W, 0.72 kW-hour

    Explanation:

    Power = Voltage * Current

    P = VI ... Equation 1

    Given: V = 120 V, I = 3 A.

    Substitute into equation 1

    P = 120 (2)

    P = 360 W.

    Hence the power usage of the device = 360 W

    Energy = Voltage*Current*time

    E = VIt ... Equation 2

    Given: V = 120 V, I = 3 A, t = 2 hr.

    Substitute into equation 2

    E = 120 (3) (2) / 1000

    E = 0.72 kW-hour

    Hence the energy of the device in kWh = 0.72 kWh
  2. 30 September, 07:08
    0
    Power P = 360 W

    Energy E = 0.72 kWh

    Explanation:

    Power can be expressed as a function of potential difference and current as;

    Power = potential difference * Current

    P = VI ... 1

    Given:

    Potential difference V = 120 V

    Current I = 3 A

    Substituting the given values into equation 1

    P = 120 * 2

    P = 360 W

    Therefore, the power usage of the device = 360 W

    Energy is the product of potential difference, current and time.

    Energy = Current*potential difference*time

    E = iVt ... 2

    Given:

    V = 120 V,

    I = 3 A,

    t = 2 hr.

    Substitute into equation 2

    E = 3*120*2 = 720 Wh : 1000 kWh/Wh

    E = 0.72 kWh

    Therefore, the energy of the device in kWh = 0.72 kWh
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