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9 August, 06:50

A 0.5 kg brick is dropped from a height of 6.0 m. It hits the ground and comes to rest. (a) What is the magnitude of the impulse exerted by the ground on the brick? N·s (b) If it takes 0.0013 s from the time the brick first touches the ground until it comes to rest, what is the magnitude of the average force exerted by the ground on the brick?

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  1. 9 August, 08:40
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    a). Impulse = 32.373 Ns

    b). Force = 2490 N

    Explanation:

    Impulse = force * time

    Force = Mgh

    But time is unknown.

    From

    V² = U² + 2as

    But V = at

    (at) ² = 0² + 2as

    But a = 9.81. (Acceleration of free fall)

    t² = (2*9.81*6) / 96.2361

    t = 1.1 sec

    Force = Mgh

    Force = 0.5*6*9.81

    Force = 29.43 N

    Impulse = 29.43*1.1

    Impulse = 32.373 Ns

    But if it takes 0.013 sec ...

    Force = 32.373/0.013

    Force = 2490 N
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