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31 May, 00:28

An object of mass 12.0 kg is placed on the pan of a spring-powered scale. The spring constant of the scale is 31.3 N/cm. What distance will the spring be compressed?

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  1. 31 May, 03:29
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    F = mg = 12x9.8 = 117.6N. According to Hooke's law, F = kx. x = F/k = 117.6/31.3 = 3.75cm. So compression in the spring is 3.75cm.
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