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21 April, 06:49

Carlos pushes a 3 kg box with a force of 9 newtons. The force of friction on the box is 3 newtons in the opposite direction. What is the acceleration of the box?

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Answers (2)
  1. 21 April, 07:48
    0
    friction = 3 N

    pushing force = 9 N

    as both are opposite in direction so their net force will be = 9-3 = 6N

    as we know that

    F = ma

    re arranging the equation

    a = F/m

    by putting values

    a = 6/3 N/kg

    a = 2 m/sec²
  2. 21 April, 10:09
    0
    The 'net' force acting on the box is (9 - 3) = 6 newtons

    in the direction that Carlos is pushing.

    Force = (mass) x (acceleration)

    6 = (3) x (acceleration)

    Divide each side by 3:

    2 m/s² = acceleration
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