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6 April, 04:30

Jason hits a volleyball with an initial velocity of 6 meters per second straight up. if the back starts at 2 meters above the floor how long will the ball be in the air

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  1. 6 April, 04:58
    0
    Vi = 6 m/s

    d = - 2 m

    a = - 9.81 m/s^2

    t = ?

    Formula

    d = vi*t + 1/2 a t^2

    - 2 = 6m/s * t -.5 * 9.81 * t^2

    Put the - 2 on the right.

    4.905 t^2 + 6 m/s t + 2 = 0

    a = - 4.905 m/s^2

    b = 6 m/s

    c = 2 m

    t = [ - b + / - square root (b^2 - 4ac) ] / (2a)

    t = [ - 6 + / - square root (6^2 - 4 * (-4.905) * 2) ] / ( - 4.905*2)

    t = [-6 + / - 8.674) / - 9.81

    t = - 14.674/-9.81

    t = 1.69 seconds.
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